Jika diketahui 2log3=a dan 3log5=b,maka nilai 6log75 adalah a.2ab+a/a+1 b.2ab+a/a c.2ab+a/a-1 d.3a+ab/a+1 e.ab+3a/a-1

6 log 75 = 3 log 75/3 log 6
              =3 log (5 x 5 x 3)/ 3log (3 x 2)
              = 3 log 5 + 3 log 5 + 3log 3 / 3 log 3 + 3 log 2
              = b +b+1/ 1+1/a
              = 2b+1/(a+1)/a
              = (2b+1)a/ a+1
              = 2ab+a/a+1    jawaban a