log (x + 1) + log (x _ 8) < 1
Matematika
nehemy07
Pertanyaan
log (x + 1) + log (x _ 8) < 1
1 Jawaban
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1. Jawaban ahreumlim
Materi : Pertidaksamaan
log(x + 1) + log(x - 8) < 1
log( (x + 1)(x - 8) ) < log10
(x + 1)(x - 8) < 10
x² - 7x - 8 < 10
x² - 7x - 18 < 0
(x + 2)(x - 9) < 0
-2 < x < 9
syarat numerus
x - 8 > 0
x > 8
jadi Himpunan penyelesaian
= {x| 8 < x < 9 }