Diketahui fungsi g (x) = 2x-1 dan (fog) (x) = 4x^2+10x+11. Rumus fungsi f (x) =
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Diketahui fungsi g (x) = 2x-1 dan (fog) (x) = 4x^2+10x+11. Rumus fungsi f (x) =
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1. Jawaban Anonyme
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g(x) = 2x - 1
fog(x) = 4x² +10x + 11
f{g(x)} = 4x² + 10x + 11
f(2x-1) = 4x² +10x + 11
y = 2x-1
2x = y+1
x = 1/2 y + 1/2
f(x) = 4(1/2 x +1/2)² + 10(1/2x + 1/2) + 11
f(x) = 4(1/4 x² + 1/2x + 1/4) + 5x + 5 + 11
f(x) = x² + 2x + 1 + 5x + 5 + 11
f(x) = x² + 7x + 17