tolong nomer 1,2,3,dan 5

Ini jawaban nomor 2 silahkan dicek dulu

1) 2p + q = 4
p = 0 => 2(0) + q = 4 => q = 4
p = 1 => 2(1) + q = 4 => q = 2
p = 2 => 2(2) + q = 4 => q = 0
hp = { ( 0,4 ) ( 1,2) ( 2,0) } ( A )

2) x - 3y - 5 = 0
x = 3y + 5
disubtitusi ke pers :
3x + 2y - 4 = 0
3(3y + 5) + 2y - 4 = 0
9y + 15 + 2y - 4 = 0
11y + 11 = 0
11y = - 11
y = - 1
disubtitusi ke pers
x = 3y + 5
x = 3(-1) + 5
x = - 3 + 5
x = 2
hp = ( 2 , - 1) ( B )

3) 2x + 3y = 12 |×3
3x + 2y = 8 |×2
maka
6x + 9y = 36
6x + 4y = 16
--------------------(-)
5x = 20
x = 4
disubtitusi ke pers
3x + 2y = 8
3(4) + 2y = 8
12 + 2y = 8
2y = 8 - 12
2y = - 4
y = - 2
nilai a + b = 4 - 2 = 2 ( B )

5) 3x + y = - 1 |×3
x + 3y = 5
maka
9x + 3y = - 3
x + 3y = 5
-------------------(-)
8x = - 8
x = - 1
disubtitusi ke pers
3x + y = - 1
3(-1) + y = - 1
(-3) + y = - 1
y = - 1 + 3
y = 2
hp = ( - 1 , 2) ( B )