Akar 9 × (7²+akar 36 per akar 25 - 2

Mapel : Matematika.
Bab : Akar, Kuadrat.
•
Akar :
= √9
= 3

Akar :
= 7² ( 7×7)
= 49

Akar :
= √36
= 6

Akar :
= √25
= 5

Jadi :
= 3 × ( 49 + 6/5 - 2 )
= 3 × 48,2
= 144,6

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Semoga membantu & selamat belajar :D

[tex] \sqrt{9( {7}^{2} + \frac{ \sqrt{36} }{ \sqrt{25} } - 2) } \\ \sqrt{9(49 + \frac{6}{5} - 2) } \\ \sqrt{9(11 - 2)} \\ \sqrt{9 \times 9} \\ \sqrt{81} = 9[/tex]
semoga membantu