Akar 9 × (7²+akar 36 per akar 25 - 2)
Matematika
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Pertanyaan
Akar 9 × (7²+akar 36 per akar 25 - 2)
2 Jawaban
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1. Jawaban syamrosa
√9.(7^2+√36/√25-2)
=3.(49+6/5-2)
=3(49+6/3)
=3(49+2)
=147+6
=153
trima ksih -
2. Jawaban Syahrudi
[tex] \sqrt{9} \times( {7}^{2} + \frac{ \sqrt{36} }{ \sqrt{25} - 2} )\\ = 3 \times (49 + \frac{6}{5 - 2} )\\ = 3 \times(49+ \frac{6}{3} \\ =3 \times( 49 + 2) \\ = 3 \times(51) \\ =153[/tex]