Jika 3 buah koin dilempar secara bersama tentukan dan jelaskan A.peluang muncul 3 gambar B.peluang muncul 1 angka C.peluang muncul kurang dari 1 angka D.peluang

A. 1/6
B. 2/6=1/3
C.1/3
D. 4/6=2/3
E. 4/6=2/3
F. 1/6

n(S) = 2³ = 8

a) A = ( G,G,G )
n(A) = 1
n(P) = 1/8

b) A = ( A,G,G) ( G,A,G) ( G,G,A)
n(A) = 3
n(P) = 3/8

c) peluang muncul kurang 1 angka,berarti tdk ada angka yg muncul
A = ( G,G,G )
n(A) = 1
n(P) = 1/8

d) A = ( G,G,G )
n(A) = 1
n(P) = 1/8

e) A = ( A,A,G ) ( A,G,A) ( G,A,A) ( G,G,A) ( G,A,G) ( A,G,G )
n( A) = 6
n(P) = 6/8 = ⅔

f) A = ( G,G,G )
n(A) = 1
n(P) = 1/8