Matematika

Pertanyaan

Penyelesaian 7y-4x-26=0 dan 8x-4y+32=0

1 Jawaban

  • 7y-4x-26=0 ==> -4x + 7y = 26 dikali 4
    8x-4y+32=0 ==> 8x - 4y = -32 dikali 7

    mnjadi:
    -16x + 28y = 104
    56x - 28y = -224
    -------------------------- -
    -72x = 328
    x = 328/(-72)
    x = - 41/9

    substitusi nilai x ke pers -4x + 7y = 26
    -4(-41/9) + 7y = 26
    164/9 + 7y = 26
    7y = 26 - 164/9
    7y = (234 - 164) / 9
    7y = 70/9
    y = (70/9) / 7
    y = 70/63
    y = 10/9

    hp nya ( -41/9 , 10/9)
    maaf kalau ad kesalahan

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