Penyelesaian 7y-4x-26=0 dan 8x-4y+32=0
Matematika
Shinzz
Pertanyaan
Penyelesaian 7y-4x-26=0 dan 8x-4y+32=0
1 Jawaban
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1. Jawaban hananda16052002
7y-4x-26=0 ==> -4x + 7y = 26 dikali 4
8x-4y+32=0 ==> 8x - 4y = -32 dikali 7
mnjadi:
-16x + 28y = 104
56x - 28y = -224
-------------------------- -
-72x = 328
x = 328/(-72)
x = - 41/9
substitusi nilai x ke pers -4x + 7y = 26
-4(-41/9) + 7y = 26
164/9 + 7y = 26
7y = 26 - 164/9
7y = (234 - 164) / 9
7y = 70/9
y = (70/9) / 7
y = 70/63
y = 10/9
hp nya ( -41/9 , 10/9)
maaf kalau ad kesalahan