tolong bantu ya kak, pakai caranya juga ya makasih..

y = x² - x + 3 oleh [tex] \left[\begin{array}{cc}0 & -1 \\ 1 & 0 \end{array}\right] \ dilanjut \ \left[\begin{array}{cc}-1 & 0 \\ 0 & 1 \end{array}\right] \\
M = \left[\begin{array}{cc} -1 & 0 \\ 0 & 1 \end{array}\right] \left[\begin{array}{cc}0 & -1 \\ 1 & 0 \end{array}\right] \\ M = \left[\begin{array}{cc}0 & 1\\ 1 & 0 \end{array}\right] \\ \left[\begin{array}{cc}x \\ y \end{array}\right] = \left[\begin{array}{cc}0 & 1 \\ 1 & 0 \end{array}\right]^{-1} \left[\begin{array}{cc}x' \\ y' \end{array}\right] \\ \left[\begin{array}{cc}x \\ y \end{array}\right] = \frac{1}{-1} \left[\begin{array}{cc} 0 & -1\\ -1 & 0 \end{array}\right] \left[\begin{array}{cc}x' \\ y' \end{array}\right] \\ \left[\begin{array}{cc}x \\ y \end{array}\right] = \left[\begin{array}{cc}0 & 1 \\ 1 & 0 \end{array}\right]\left[\begin{array}{cc}x' \\ y' \end{array}\right]
\\ \left[\begin{array}{cc}x \\ y \end{array}\right]= \left[\begin{array}{cc}y' \\ x' \end{array}\right] [/tex]

Didapat x = y' , y = x'

Maka
y = x² - x + 3
➙ x' = (y')² - y' + 3
➙ x = y² - y + 3
Atau
➙ y² - x - y + 3 = 0