Bentuk sederhana dari 2/x+2 -3/x+3

maaf klo slh...
2(x+3)-3(x+2)=
2x+6-3x-6 =
2x-3x+6-6 =
-x/(x+2)(x+3)

Mapel : Matematika (Kelas VII SMP)
Materi : Aljabar
Indikator : Mengoperasikan bilangan berbentuk aljabar

Langkah Penyelesaian dan Jawaban :

[tex]\frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd} \\\\ \frac{2}{x+2}-\frac{3}{x + 3} = \frac{2(x + 3) - 3(x + 2)}{(x + 2) (x + 3)}\\\\ \frac{2}{x+2}-\frac{3}{x + 3} = \frac{2x + 6 - 3x - 6}{(x + 2)(x + 3)} \\\\ \frac{2}{x+2}-\frac{3}{x + 3} = \frac{2x - 3x + 6 - 6}{(x + 2)(x + 3)}\\\\ \frac{2}{x+2}-\frac{3}{x + 3} = \frac{- x}{(x + 2)(x + 3)}\\\\ \therefore\boxed{-\frac{x}{(x + 2)(x + 3)}}[/tex]