tentukan pesamaan ggaris yang melalui titik (3,2)dan (6,8)

( y - y1) / ( y2 - y1) = ( x - x1) / ( x2 - x1)
( y - 2) / ( 8 - 2) = ( x - 3) / ( 6 - 3)
( y - 2) / 6 = ( x - 3) / 3
3 ( y - 2) = 6 ( x - 3)
3y - 6 = 6x - 18
3y - 6x = - 18 + 6
3y - 6x = - 12 ( disederhanakan)
y - 2x = - 4

(3,2) (6,8)
[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} [/tex]

[tex] \frac{y - 2}{8 - 2} = \frac{x - 3}{6 - 3} [/tex]

[tex] \frac{y - 2}{6} = \frac{x - 3}{3} [/tex]

=3(y-2) = 6(x-3)
=3y-6 =6x-18
=-6x-3y-6-18
=-6x-3y-12

maaf klo slah