Matematika

Pertanyaan

Pangkat 3 log akar 6
--------------------------------(PER)
(Pangkat 3 log 18)pangkat 2-(pangkat 3 log 2)pangakat 2

1 Jawaban

  • [tex]\frac{^3\log{\sqrt{6}}}{\left(^3\log{18}\right)^2-\left(^3\log{2}\right)^2}=\frac{^3\log{6^{\frac{1}{2}}}}{\left(^3\log{18}+^3\log{2}\right)\left(^3\log{18}-^3\log{2}\right)}\\=\frac{\frac{1}{2}\times ^3\log{6}}{^3\log{36}\times ^3\log{9}}\\=\frac{1}{2}\times\frac{^3\log{6}}{^3\log{6^2}\times 2}\\=\frac{1}{4}\times\frac{^3\log{6}}{2\times ^3\log{6}}\\=\frac{1}{8}[/tex]

    hmmm..

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