diket 2log3=a tentukan a.4log72 b.16log12 c.8log27

LOgaritma

²log 3 = a

4'log 72
= 1/2 (²log (2³ . 3²))
= 1/2 (3 + 2 . ²log 3)
= 1/2 (3 + 2a)

16'log 12
= 1/4 (²log (2² . 3))
= 1/4 (2 + ²log 3)
= 1/4 (2 + a)

8'log 27
= (2³)'log 3³
= ²log 3
= a