tentukan persamaan garis lurus yang melalui titik A(-3,-6)dan B(-8,-12)

y-y1/y2-y1 = x-x1/x2-x1
y-(-6)/-12-(-6) = x-(-3)/-8-(-3)
y+6/-12+6 = x+3/-8+3
y+6/-6 = x+3/-5
-5(y+6) = -6(x+3)
-5y-30 = -6x-18
-5y = -6x-18+30
-5y = -6x+12
-1 x (-5y) = -1(-6x+12)
5y = 6x-12

*semoga membantu. sukses selalu ^_^