3x+2y=12 dan 2x+3y=18

3x+2y=12 dan 2x+3y=18

eliminasi

3x+2y=12   |x2| 6x+4y =24

2x+3y=18   |x3| 6x+9y = 54

                        ----------------- -

                                 -5y=-30

                                    y =-30/-5 = 6

substitusi ke 3x+2y = 12

3x = 12 - 2.6

x = 12 - 12 / 3

x = 0 / 3

x = 0

jadi nilai y = 6 dan x =0