bantu plis besok diantar

log 5 + log 2 = log (5 . 2) = log 10 = 1

2'log 3 - 4'log 2 = 2'log 3 - 1/2 . 2'log 2 = 2'log 3 - 1/2

2'log 6(x + 3) = 2'log (5x + 4) 
6(x +3) = 5x + 4
6x - 5x = -18 + 4
x = -14
#cek_soal

log (x² + 5x + 4) = 7'log (x² + 5x + 4)
x² + 5x + 4 = 1
x² + 5x + 3 = 0
rumus abc :
x1 = (-5 + √13)/2 atau x2 = (-5 - √13)/2

(x + 6)'log (6x + 1) = (x + 6)'log (6x + 1)
6x + 1 > 0
x > 1/6

³log² x + 5 . ³log x + 6 = 0
(³log x + 2)(³log x + 3) = 0
³log x = -2 → x = 3^-2 = 1/9
³log x = -3 → x = 3^-3 = 1/27