Akar akar dari persamaan kuadrat 2x² + 5x-3=0 adalah x1 dan x2 Nilai x1² + x2²

2x²+5x-3=0
(2x-1)(x+3)=0
2x= 1
x=1/2 ataau x=-3

x1²+x2²= 1/2²+ -3²=9 1/4

2x² + 5x - 3 = 0

a = 2
b = 5
c = -3

x₁ + x₂ = -b/a
            = -5/2

x₁ . x₂ = c/a
           = -3/2

x₁² + x₂² = (x₁ + x₂)² - 2.x₁.x₂
              = (-5/2)² - 2(-3/2)
              = 25/4 + 3
              = 25/4 + 12/4
              = 37/4
              = 9 1/4