tentukan persamaankuadrat baru yang akarnya 5 dan-2

x₁ = 5
x₂ = -2

(x - x₁)(x - x₂) = 0
(x - 5)(x - (-2)) = 0
(x - 5)(x + 2) = 0
x² + 2x - 5x - 10 = 0
x² - 3x - 10 = 0

Solusi:

(x - x1)(x - x2) = 0
(x - 5)(x + 2) = 0
x² - 3x - 10 = 0