persamaan garis melalui titikA(3,-5)dan titikB(0,2)adalah

y - y1/y2 - y1 = x - x1/x2 - x1
y-(-5)/2-(-5) = x - 3/0 - 3

y+5/7 = x - 3/-3

-3(y+5) = 7(x-3)
-3y-15 = 7x-21
-3y = 7x-21+15
-3y = 7x-6
0 = 7x + 3y -6

(y-yA)/(yB-yA) = (x-xA)/(xB-xA)
(y-(-5))/(2-(-5)) = (x-3)/(0-3)
(y+5)/7 = (x-3)/-3
-3 (y+5) = 7 (x-3)
-3y -15 = 7x -21
-3y -7x +6 =0