Matematika

Pertanyaan

tentukan himpunan penyelesaian dari sistem persamaan berikut dengan cara eliminasi
a. 3( x + y ) - 2x = 19 dan
5x - 3( x + y ) = 22
b. 4( x - 3y ) + 7y =5 dan
9y - 4( x - 3y ) = 43
mohon bantuannya please
nanti hari jumat dikumpulkan
<_>

2 Jawaban

  • a) 3( x + y ) - 2x = 19
    3x + 3y - 2x = 19
    x + 3y = 19 ... pers 1
    5x - 3(x + y) = 22
    5x - 3x - 3y = 22
    2x - 3y = 22 ... pers 2

    pers 1 & 2 dieliminasi
    x + 3y = 19
    2x - 3y = 22
    ------------------(+)
    3x = 41
    x = 41/3

    x + 3y = 19 |×2
    2x - 3y = 22
    maka
    2x + 6y = 38
    2x - 3y = 22
    --------------------(-)
    9y = 16
    y = 16/9

    hp = { 41/3 , 16/9 }

    b) 4 ( x - 3y) + 7y = 5
    4x - 12y + 7y = 5
    4x - 5y = 5 ... pers 1
    9y - 4 ( x - 3y ) = 43
    9y - 4x + 12y = 43
    21y - 4x = 43
    - 4x + 21y = 43 ... pers 2

    pers 1 & 2 dieliminasi
    4x - 5y = 5
    - 4x + 21y = 43
    ---------------------(+)
    16y = 48
    y = 3

    pers 1 & 2
    4x - 5y = 5 |×21
    - 4x + 21y = 43 |×5
    maka
    84x - 105y = 105
    - 20x + 105y = 215
    -----------------------------(+)
    64x = 320
    x = 5

    hp = ( 5 , 3 )
  • [tex]$\begin{align}-2x+3(x+y)&=19\\\underline{5x-3(x+y)}&\underline{\ =22\ \ +}\\3x&=41\\x&=\frac{41}3=13\frac23\end[/tex]


    [tex]$\begin{align}-2x+3(x+y)&=19\\-2x+3x+3y&=19\\x+3y&=19&&\to\text{kalikan 2}\\2x+6y&=38\\\\5x-3(x+y)&=22\\5x-3x-3y&=22\\2x-3y&=22\\\\2x+6y&=38\\\underline{2x-3y}&\underline{\ =22\ \ -}\\9y&=16\\y&=\frac{16}9=1\frac79\end[/tex]


    [tex]\boxed{\text{HP}=\left\{13\frac23,\ 1\frac79\right\}}[/tex]
    _____________________________________________________

    [tex]$\begin{align}4(x-3y)+7y&=\ \ 5\\\underline{-4(x-3y)+9y}&\underline{\ =43\ \ +}\\16y&=48\\y&=\ \ 3\end[/tex]


    [tex]$\begin{align}4(x-3y)+7y&=5\\4x-12y+7y&=5\\4x-5y&=5&&\to\text{kalikan 21}\\84x-105y&=105\\\\-4(x-3y)+9y&=43\\-4x+12y+9y&=43\\-4x+21y&=43&&\to\text{kalikan 5}\\-20x+105y&=215\\\\84x\ -\ 105y&=105\\\underline{-20x+105y}&\underline{\ =215\ \ +}\\28x&=320\\x&=\ \ \ 5\end[/tex]


    [tex]\boxed{\text{HP}=\{5,\ 3\}}[/tex]



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