Tentukan himpunan penyelesaian persamaan lineat A.24m=12 B.3z+11 =-28 C.25-4y=6y+15 Jika xadalah asli, tentukan himpunan penyelesaian dari persama linear beriku

A.
[tex]24m = 12 \\ m = \frac{12}{24} \\ m = \frac{1}{2} [/tex]
B.
[tex]3z + 11 = - 28 \\ 3z = - 28 - 11 \\ 3z = - 39 \\ z = \frac{ - 39}{3} \\ z = - 13[/tex]
C.
[tex]25 - 4y = 6y + 15 \\ - 4y - 6y = 15 - 25 \\ - 10y = - 10 \\ y = \frac{ - 10}{ - 10} \\ y = 1[/tex]
A.
[tex]6x + 5 = 26 - x \\ 6x + x = 26 - 5 \\ 7x = 21 \\ x = \frac{21}{7} \\ x = 3[/tex]
B.
[tex]2 - 4x = 3 \\ - 4x = 3 - 2 \\ - 4x = 1 \\ x = - \frac{1}{4} [/tex]
C.
[tex]x - 12 = 2x + 36 \\ x - 2x = 36 + 12 \\ - x = 48 \\ x = - 48[/tex]