tentukan fungsi inversdari a,f(x)=5‹2x + 1 b,f(x)=3‹-2x+4 - 5 ‹=pangkat

jawab

f(x) = 5²ˣ⁺¹
y = 5²ˣ⁺¹
log y = (2x+1) log 5
2x + 1 = log y/log 5
2x + 1 = ⁵log y
2x = ⁵log y - 1 = ⁵log y - ⁵log 5
2x= ⁵log (y/5)
x = 1/2 . ⁵log (y/5)
x = ⁵log √(y/5)
f⁻¹(x) = ⁵log √(x/5)

f(x) = 3²ˣ⁺⁴ - 5
y = 3²ˣ⁺⁴ - 5
3²ˣ⁺⁴ = y + 5
log (3²ˣ⁺⁴) = log(y+5)
(2x+4) log 3 = log(y+5)
2x+4 = ³log(y+5)
2x = ³log (y+5) - 4 = ³log(y+5) - ³log 3⁴
2x = ³log (y+5)/(81)
x = 1/2. ³log ((y+5)/81)
x = ³log √ {(y+5)/81 }
f⁻¹(x) =  ³log √{ (x+5) / 81 }