tolong yang jago matematika nomer 4

jawab

gradien garis  = m
m= (y2-y1)/(x2-x1)

P(6,-3)
Q (-2,3)

mPQ = (3 - (-3)) / (-2 - 6)
mPQ = (6)/(-8)
mPQ =  - 3/4

garis AB sejajar garis PQ
mAB = mPQ = - 3/4

garis KL tegak lurus garis PQ
mKL . mPQ= -1
mKL =  - 1/mPQ = - 1/ (-3/4)
mKL = 4/3