jika f(x)=2x-3 dan (gof)(x)= 6x+10 maka g-¹(x) adalah pakai cara! mohon.

jawab

f(x) = 2x - 3
gof(x) = 6x + 10
g{f(x)} = 6x +10
g(2x -3) = 6x +10
g(2x-3) = 3(2x -3) + 19
g(x) = 3x + 19

y = 3x + 19
3x = y - 19
x = 1/3(y - 19)

g⁻¹(y) = 1/3 (y-19)
g⁻¹(x) = 1/3 (x - 19)