f(x) = x2 - 4 g(x) = -4x + 1 ditanya a. ( f o g)(x) b. (g o f)(x)
Matematika
widyarsa12
Pertanyaan
f(x) = x2 - 4
g(x) = -4x + 1
ditanya
a. ( f o g)(x)
b. (g o f)(x)
g(x) = -4x + 1
ditanya
a. ( f o g)(x)
b. (g o f)(x)
2 Jawaban
-
1. Jawaban ahreumlim
Materi : Fungsi Komposisi
f(x) = x² - 4
g(x) = -4x + 1
fog(x)
= f(g(x))
= (-4x + 1)² - 4
= 16x² - 8x + 1 - 4
= 16x² - 8x - 3
gof(x)
= g(f(x))
= -4x + 1
= -4(x² - 4) + 1
= -4x² + 16 + 1
= -4x² + 17 -
2. Jawaban Anonyme
B. g(x)= -4x+1
gof(x)
= g(f(x))
= -4x+1
= -4(x^2-4)+1
= -4x^2+16+1
= -4x^2+17
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