Matematika

Pertanyaan

yang nomor 4 nya ya.tolong di bantu kak
yang nomor 4 nya ya.tolong di bantu kak

1 Jawaban

  • a) y - y1 = m ( x - X1)
    y - 4 = - ⅓ ( x - 0 )
    y = - ⅓ x + 4 ( dikali 3)
    3y = - x + 12
    3y + x = 12

    b) y - y1 = m ( x - X1)
    y + 2 = - 4 ( x - 1 )
    y = - 4x + 4 - 2
    y + 4x = 2

    c) ( y - y1 ) / ( y2 - y1 ) = ( x - X1 ) / ( x2 - X1 )
    ( y - 6 ) / ( 4 - 6 ) = ( x - 1) / ( 7 - 1)
    ( y - 6 ) / ( - 2) = ( x - 1 ) / 6
    6 ( y - 6 ) = (-2) ( x - 1 )
    6y - 36 = - 2x + 2
    6y + 2x = 2 + 36
    6y + 2x = 38 ( disederhanakan)
    3y + x = 16

    d) y = x - 6
    m = 1
    sejajar m1 = m2 = 1
    pers garis
    y - y1 = m ( x - X1)
    y + 1 = 1 ( x + 2)
    y = x + 2 - 1
    y = x + 1

    g) m = ( y2 - y1 ) / ( x2 - X1 )
    m = ( - 2 + 4 ) / ( 0 + 5 )
    m = 2 / 5
    gradien saling tegak lurus
    m1 . m2 = - 1
    2/5 . m2 = - 1
    m2 = - 1 ÷ 2/5
    m2 = - 5/2
    pers garis
    y - y1 = m ( x - X1)
    y + 4 = - 5/2 ( x + 5)
    y = - 5/2 x - 25/2 - 4 ( dikali 2)
    2y = - 5x - 25 - 8
    2y + 5x = - 33