Matematika

Pertanyaan

tentukan himpunan penyelesaian berikut!!!
1)5g-2h=4 dan 3g=4h-6
2)2r+3s=5 dan 3r-2s=17
(1&2 guankan cara subtitusi)

1 Jawaban

  • 1) 5g - 2h = 4
    - 2h = - 5g + 4
    2h = 5g - 4
    disubtitusi ke pers
    3g = 4h - 6
    3g = ( 2•2h ) - 6
    3g = 2 ( 5g - 4) - 6
    3g = 10g - 8 - 6
    3g - 10g = - 14
    - 7g = - 14
    g = 2
    disubtitusi ke pers
    2h = 5g - 4
    2h = 5(2) - 4
    2h = 10 - 4
    2h = 6
    h = 3
    hp = { 2 , 3 }

    2) 2r + 3s = 5
    2r = 5 - 3s
    r = 5/2 - 3/2 s
    subtitusi ke pers
    3r - 2s = 17
    3(5/2 - 3/2 s ) - 2s = 17
    15/2 - 9/2 s - 2s = 17 ( dikali 2)
    15 - 9s - 4s = 34
    - 13s = 34 - 15
    - 13s = 19
    s = - 19/13
    disubtitusi ke pers
    r = 5/2 - 3/2s
    r = 5/2 - 3/2(-19/13)
    r = 5/2 + 57/26
    r = 65/26 + 57/26
    r = 122/26
    r = 61/13
    hp = { 61/13 , - 19/13 }

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